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=C^2/25+3C+100
We move all terms to the left:
-(C^2/25+3C+100)=0
Domain of the equation: 25+3C+100)!=0We get rid of parentheses
We move all terms containing C to the left, all other terms to the right
3C+100)!=-25
C∈R
-C^2/25-3C-100=0
We multiply all the terms by the denominator
-C^2-3C*25-100*25=0
We add all the numbers together, and all the variables
-1C^2-3C*25-2500=0
Wy multiply elements
-1C^2-75C-2500=0
a = -1; b = -75; c = -2500;
Δ = b2-4ac
Δ = -752-4·(-1)·(-2500)
Δ = -4375
Delta is less than zero, so there is no solution for the equation
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